Startfraction 6 minus startroot 25 endroot over 4 endfraction.

Find the exact value of cosine (startfraction 5 pi over 6 endfraction) cosine (startfraction pi over 12 endfraction) + sine (startfraction 5 pi over 6 endfraction) sine (startfraction pi over 12 endfraction) startfraction startroot 2 endroot over 2 endfraction negative startfraction startroot 2 endroot over 2 endfraction negative startfraction startroot 3 …Apr 3, 2020 · Multiplying startfraction 3 over startroot 17 endroot minus startroot 2 endroot endfraction by which fraction will produce an equivalent fraction with a rational denominator? startfraction startroot 17 endroot minus startroot 2 endroot over startroot 17 endroot minus startroot 2 endroot endfraction startfraction startroot 17 endroot startroot 2 endroot over startroot 17 endroot startroot 2 ... In 1953, CalTech geochemist Clair Patterson came up with an estimate for Earth's age that still holds today. Advertisement Advertisement If you look up the age of Earth on science ...Given: sine (a) = startfraction 5 over 13 endfraction, startfraction pi over 2 endfraction < a < pi and tangent (b) = negative startroot 13 endroot, startfraction pi over 2 endfraction < b < pi what is tan(a – b)? startfraction 5 12 startroot 13 endroot over 12 minus 5 startroot 13 endroot endfraction startfraction 12 minus 5 ...

What are the solutions of x2 = 8 – 5x? startfraction 5 minus startroot 57 endroot over 2 endfraction comma startfraction 5 + startroot 57 endroot over 2 endfraction startfraction negative 5 minus startroot 57 endroot over 2 endfraction comma startfraction negative 5 + startroot 57 endroot over 2 endfraction …Which expression is equivalent to log Subscript 8 Baseline 4 a (StartFraction b minus 4 Over c Superscript 4 Baseline EndFraction)? log Subscript 8 Baseline 4 + log ... Superscript 4 Baseline Over RootIndex 3 StartRoot x squared + 8 EndRoot EndFraction? 4 log Subscript w Baseline StartFraction x squared Over 1296 …Dec 21, 2022 · What is the following quotient? StartFraction 9 + StartRoot 2 EndRoot Over 4 minus StartRoot 7 EndRoot EndFraction StartFraction 9 StartRoot 7 EndRoot + StartRoot 14 EndRoot Over negative 3 EndFraction StartFraction 36 minus 9 StartRoot 7 EndRoot + 4 StartRoot 2 EndRoot minus StartRoot 14 EndRoot EndFraction StartFraction 36 + 9 StartRoot 7 EndRoot + 4 StartRoot 2 EndRoot + StartRoot 14 ...

Solve the equation by using the quadratic formula. 3 x squared minus 1 = 5 x a. startfraction 5 startroot 13 endroot over 6 endfraction, startfraction 5 minus startroot 13 endroot over 6 endfraction b. startfraction negative 5 startroot 13 endroot over 6 endfraction, startfraction negative 5 minus startroot 13 endroot over 6 …The value of limit of startfraction startroot x + 2 endroot minus 3 over x minus 7 endfraction when x approaches 7 is 1/6.. How to evaluate a function for a given value? To evaluate a function for a particular value, plug in the value of the variable in the function.. The expression given in the problem is,. Multiply the factor √(x+2)+3 above and …

Dec 18, 2019 · StartFraction 4 Over x EndFraction – x2 - 16 is not a polynomial because it contains a term with a negative exponent (4/x is the same as 4x^-1). 3.9x3 – 4.1x2 + 7.3 is a polynomial as it involves the operations of addition and subtraction, and non-negative exponents of x. Determine the zeros of the function f(x) = 3x2 – 7x + 1. x = StartFraction 7 plus or minus StartRoot 37 EndRoot Over 6 EndFraction x = StartFraction negative 7 plus or minus StartRoot 37 EndRoot Over 6 EndFraction x = StartFraction 7 plus or minus StartRoot 61 EndRoot Over 6 EndFraction x = StartFraction negative 7 plus or …Oct 14, 2019 · Ramiya is using the quadratic formula to solve a quadratic equation. Her equation is x = StartFraction negative 3 plus or minus StartRoot 3 squared minus 4(1)(2) EndRoot Over 2(1) EndFraction after substituting the values of a, b, and c into the formula. Which is Ramiya’s quadratic equation? The simplification of the mathematical expression 11√45 - 4√5 is 29√5 option third is correct.. What is an expression? It is defined as the combination of constants and variables with mathematical operators.. The question is incomplete.. The complete question is in the picture, please refer to the attached picture. We have a mathematical expression:

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Dec 28, 2019 · One-fourth RootIndex 6 StartRoot 2 EndRoot StartRoot 2 EndRoot StartFraction StartRoot 2 EndRoot Over 2 EndFraction Answer is RootIndex 6 StartRoot 2 EndRoot B on edg star 5.0 /5

Verified answer. Which equation is the inverse of (x minus 4) squared minus two-thirds = 6y minus 12? y = one-sixth x squared minus four-thirds x + StartFraction 43 Over 9 EndFraction y = 4 plus-or-minus StartRoot 6 x minus StartFraction 34 Over 3 EndFraction EndRoot y = negative 4 plus-or-minus StartRoot …StartFraction 4 Over x EndFraction – x2 - 16 is not a polynomial because it contains a term with a negative exponent (4/x is the same as 4x^-1). 3.9x3 – 4.1x2 + 7.3 is a polynomial as it involves the operations of addition and …tRoot 2 EndRoot minus 6 StartRoot 3 EndRoot Over 5 EndFraction StartFraction 3 StartRoot 6 EndRoot minus 4 StartRoot 3 EndRoot Over 24 EndFraction StartFraction StartRoot 3 EndRoot Over 12 EndFraction StartFraction StartRoot 3 EndRoot Over 2 EndFraction. ... 10/12x+4/6=-9 10/12x=-50/6 10/12x=-25/3. …Click here 👆 to get an answer to your question ️ Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 ... 4 * 1.5c = 7. Evaluate. 25 - 6c = 7. Subtract ... negative 5 + StartRoot 57 EndRoot Over 2 EndFraction StartFraction negative 5 minus StartRoot 7 EndRoot Over 2 …C. 3 StartRoot 2 EndRoot minus StartRoot 22 EndRoot + 2 StartRoot 3 EndRoot minus 4 D. 2 StartRoot 3 EndRoot + 6 minus 2 StartRoot 15 EndRoot. loading. See answers ... 6 EndRoot minus StartRoot 2 EndRoot Over 2 EndFraction StartFraction StartRoot 6 EndRoot minus StartRoot 2 EndRoot Over 4 EndFraction …May 21, 2023 · Which equation is the inverse of (x minus 4) squared minus two-thirds = 6y minus 12? y = one-sixth x squared minus four-thirds x + StartFraction 43 Over 9 EndFraction y = 4 plus-or-minus StartRoot 6 x minus StartFraction 34 Over 3 EndFraction EndRoot y = negative 4 plus-or-minus StartRoot 6 x minus StartFraction 34 Over 3 EndFraction EndRoot ... Consider w = startfraction startroot 2 endroot over 2 endfraction (cosine (225 degrees) i sine (225 degrees) ) and z = 1(cos(60°) isin(60°)). what is w z expressed in rectangular form? startfraction startroot 3 endroot minus 1 over 4 endfraction i startfraction startroot 3 endroot 1 over 4 endfraction i startfraction startroot 3 …

Dec 28, 2019 · One-fourth RootIndex 6 StartRoot 2 EndRoot StartRoot 2 EndRoot StartFraction StartRoot 2 EndRoot Over 2 EndFraction Answer is RootIndex 6 StartRoot 2 EndRoot B on edg star 5.0 /5 May 19, 2023 · The given quotient is (3√8 / 4√6) / (12√2 - 6√3 / 5).To simplify the given expression, we can multiply the numerator and denominator by the conjugate of the denominator expression. This will help eliminate the radicals in the denominator. Jan 18, 2022 · What is the following quotient? StartFraction 3 StartRoot 8 EndRoot Over 4 StartRoot 6 EndRoot EndFraction StartFraction 12 StartRoot 2 EndRoot minus 6 StartRoot 3 EndRoot Over 5 EndFraction StartFraction 3 StartRoot 6 EndRoot minus 4 StartRoot 3 EndRoot Over 24 EndFraction StartFraction StartRoot 3 EndRoot Over 12 EndFraction StartFraction StartRoot 3 EndRoot Over 2 EndFraction 03/25/2020. Mathematics; Middle School; verified. ... squared minus two-thirds = 6y minus 12? y = one-sixth x squared minus four-thirds x + StartFraction 43 Over 9 EndFraction y = 4 plus-or-minus StartRoot 6 x minus StartFraction 34 Over 3 EndFraction EndRootWhat is the exact value of cosine startfraction 7 pi over 12 endfraction? a. startfraction startroot 6 endroot minus startroot 2 endroot over 4 endfraction b. startfraction startroot 6 endroot startroot 2 endroot over 4 endfraction .c startfraction 2 startroot 2 endroot minus startroot 6 endroot over 4 endfraction d. startfraction …Apr 22, 2023 · StartFraction StartRoot 6 EndRoot minus StartRoot 2 EndRoot Over 2 EndFraction StartFraction StartRoot 6 EndRoot minus StartRoot 2 EndRoot Over 4 EndFraction ...

Feb 11, 2020 · 4x3 – StartFraction 2 Over x EndFraction. 2y3 + 5y2 – 5y. 3y3 – StartRoot 4 y EndRoot –xyStartRoot 6 EndRoot. Now, 4x^3-2y^3+5y^2-5y . The polynomial has a degree of 3 (both y and x have an exponent of 3) 3y3-xy=3y^3+xy . The polynomial has a degree of 3 also (y has an exponent of 3)

To rationalize the denominator of StartFraction 5 minus StartRoot 7 EndRoot Over 9 minus StartRoot 14 EndRoot EndFraction, we should multiply the expression by StartFraction 9 + StartRoot 14 EndRoot Over 9 + StartRoot 14 EndRoot EndFraction. Goal of rationalization: To eliminate any radicals (like square roots) from …The given quotient is (3√8 / 4√6) / (12√2 - 6√3 / 5).To simplify the given expression, we can multiply the numerator and denominator by the conjugate of the denominator expression.This will help eliminate the radicals in the denominator.. Multiply the numerator and denominator by the conjugate of the …A. x = negative 11 plus-or-minus StartFraction 25 Over 2 EndFraction B. x = negative eleven-halves plus-or-minus StartFraction 25 Over 2 EndFraction C. x = negative 11 plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction D.x = negative eleven-halves plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 …In finance, operating income refers to the amount of profit a business generates, minus any wages, cost of goods sold (COGS) and other operating expenses... Operating income is a v...Jun 9, 2022 · What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction x = StartFraction 5 plus or minus 10 StartRoot 5 EndRoot Over 2 EndFraction x = StartFraction negative 5 plus or minus 10 StartRoot 5 EndRoot Over 2 EndFraction x = StartFraction ... Multiplying StartFraction 3 Over StartRoot 17 EndRoot minus StartRoot 2 EndRoot EndFraction by which fraction Get the answers you need, now!Solve the equation by using the quadratic formula. 3 x squared minus 1 = 5 x a. startfraction 5 startroot 13 endroot over 6 endfraction, startfraction 5 minus startroot 13 endroot over 6 endfraction b. startfraction negative 5 startroot 13 endroot over 6 endfraction, startfraction negative 5 minus startroot 13 endroot over 6 …The exact value of sin 170° cos 55° cos 170° sin 55° is startfraction startroot 3 endroot over 2 endfraction negative.. The exact value of sin 170° cos 55° cos 170° sin 55° can be calculated using the trigonometric identities.. First, the double angle identities for sine and cosine can be used to express the given …

May 23, 2020 · What is the following quotient? StartFraction 3 StartRoot 8 EndRoot Over 4 StartRoot 6 EndRoot EndFraction StartFraction 12 StartRoot 2 EndRoot minus 6 StartRoot 3 EndRoot Over 5 EndFraction StartFraction 3 StartRoot 6 EndRoot minus 4 StartRoot 3 EndRoot Over 24 EndFraction StartFraction StartRoot 3 EndRoot Over 12 EndFraction StartFraction StartRoot 3 EndRoot Over 2 EndFraction

May 31, 2023 · Click here 👆 to get an answer to your question ️ Consider w = StartFraction StartRoot 2 EndRoot Over 2 ... StartRoot 2 EndRoot Over 2 EndFraction (cosine (225 ...

And since -2π/3 is the same angle as 2π - 2π/3 = 4π/3, the right answer is: 18 (cos (4π/3) + i sin (4π/3)) Therefore, using trigonometry identities, we know that the polar form of -9-9√3i is (D) 18 (cos (4π/3) + isin (4π/3)). What is the polar form of Negative 9 minus 9 I StartRoot 3 EndRoot? a. 9 (cosine (StartFraction pi over 3 ...03/25/2020. Mathematics; Middle School; verified. ... squared minus two-thirds = 6y minus 12? y = one-sixth x squared minus four-thirds x + StartFraction 43 Over 9 EndFraction y = 4 plus-or-minus StartRoot 6 x minus StartFraction 34 Over 3 EndFraction EndRootWhat is the exact value of cos(c d), given sine c = startfraction 24 over 25 endfraction for c in quadrant ii and cosine d = negative three-fourths for d in quadrant iii? star. 5/5. heart. 2. ... given sine (alpha) = negative four-fifths= and cos (beta) minus StartFraction 5 Over 8 EndFraction = for α in Quadrant III and ß in Quadrant II. star. 5.0/5. heart. 29. verified. …One-half = StartFraction 8 Over x Endfraction. x = 16 Cosecant 60 degrees = StartFraction 8 Over x EndFraction. StartFraction StartRoot 3 EndRoot Over 2 EndFraction = StartFraction 8 Over x EndFraction. x times StartRoot 3 EndRoot = 16. x = StartFraction 16 Over StartRoot 3 EndRoot EndFraction. x = StartFraction 16 …The inverse of the given function, y = 16x² + 1 is: B. y = ±√(x - 1)/16. What is an inverse function? In Mathematics, an inverse function can be defined as a type of function that is obtained by reversing (undoing) the operation of a given function (f(x)).. Generally speaking, a given function (f(x)) and its inverse function has the following property …What is the exact value of cosine startfraction 7 pi over 12 endfraction? a. startfraction startroot 6 endroot minus startroot 2 endroot over 4 endfraction b. startfraction startroot 6 endroot startroot 2 endroot over 4 endfraction .c startfraction 2 startroot 2 endroot minus startroot 6 endroot over 4 endfraction d. startfraction …Answer. No one rated this answer yet — why not be the first? 😎. BenicioBrody. report flag outlined. Final answer: After simplifying the original …For the complex number z = StartFraction 5 StartRoot 3 EndRoot Over 4 EndFraction minus StartFraction 5 Over 4 EndFraction i ,what is the polar form? correct one - A.) z = five-halves (cosine (StartFraction pi Over 6 EndFraction) + I sine (StartFraction pi Over 6 EndFraction) B.) z = five-fourths (cosine (StartFraction pi …Assume x greater-than 0 RootIndex 4 StartRoot StartFraction 3 Over 2 x ... StartFraction RootIndex 4 StartRoot 6 x EndRoot Over 2 x EndFraction ... y = negative StartRoot x + 5 EndRoot minus 3. report flag outlined. Advertisement. heart. Loved by …

Which equation is the inverse of (x minus 4) squared minus two-thirds = 6y minus 12? y = one-sixth x squared minus four-thirds x + StartFraction 43 Over 9 EndFraction y = 4 plus-or-minus StartRoot 6 x minus StartFraction 34 Over 3 EndFraction EndRoot y = negative 4 plus-or-minus StartRoot 6 x minus StartFraction …Find the exact value of cosine (startfraction 5 pi over 6 endfraction) cosine (startfraction pi over 12 endfraction) + sine (startfraction 5 pi over 6 endfraction) sine (startfraction pi over 12 endfraction) startfraction startroot 2 endroot over 2 endfraction negative startfraction startroot 2 endroot over 2 endfraction negative …Which shows the correct substitution of the values a, b, and c from the equation –2 = –x + x2 – 4 into the quadratic formula? Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction x = StartFraction negative (negative 1) plus or minus StartRoot (negative 1) squared …The prime factorisation of √25 = 5. The prime factorisation of √441 = 21. The simplest form of √25 / 441 is 5 / 21. How to simplify an expression? simplify √25 / 441. Using indices method, Therefore, The prime factorisation of √25 = 5. The prime factorisation of √441 = 21. The expression √25 / 441 in the simplest form is as ...Instagram:https://instagram. lottery numbers in texassound of freedom showtimes near showcase cinemas warwickeros nashville tseras tour hoodie Which are the solutions of x2 = –5x + 8? StartFraction negative 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFraction negative 5 + StartRoot 57 EndRoot Over 2 EndFraction StartFraction negative 5 minus StartRoot 7 EndRoot Over 2 EndFraction comma StartFraction negative 5 + … when is amavasya this monthmujer asiendo sexo con perro The two solutions are Plus or minus StartFraction StartRoot 7 EndRoot Over 2 EndFraction. loading. See answer. ... Check all that apply StartFraction 5 Over 2 EndFraction + StartFraction StartRoot 33 EndRoot Over 4 EndFraction StartFraction 5 Over 2 EndFraction + StartFraction StartRoot 33 EndRoot Over 2 EndFraction … the chickahominy crossword startfraction 9 + startroot 2 endroot over 4 minus startroot 7 ... StartFraction StartRoot 3 EndRoot minus StartRoot 6 EndRoot Over 4 EndFraction B)StartFraction 2 + StartRoot 3 EndRoot minus 2 StartRoot 2 EndRoot minus StartRoot 6 ... A triangular prism and a triangular pyramid have …One-fourth RootIndex 6 StartRoot 2 EndRoot StartRoot 2 EndRoot StartFraction StartRoot 2 EndRoot Over 2 EndFraction Answer is RootIndex 6 StartRoot 2 EndRoot B on edg star 5.0 /5StartFraction 1 Over 1 StartRoot 3 EndRoot EndFraction. Get the answers you need, now! See what teachers have to say about Brainly's new learning tools! ... 25 answers. 1.8K people helped. report flag outlined. Answer: On edge. ... StartRoot 3 EndRoot Over 4 EndFraction StartFraction 1 + StartRoot 3 EndRoot Over 4 …